on 15-03-2013 13:56
on 15-03-2013 13:56
Here's an interesting game:
Can we make all the numbers from 0 to 21 just by using 2, 3 and 5?
It is possible to do.
So for example;
0 = 5 - 3 - 2
10 = 5 + 3 + 2
on 15-03-2013 14:03
on 15-03-2013 14:03
on 15-03-2013 14:05
on 15-03-2013 14:05
on 15-03-2013 15:19
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15-03-2013 15:45 - edited 15-03-2013 15:46
15-03-2013 15:45 - edited 15-03-2013 15:46
7 = (5*2) -3
16= (5*3)-2
21=(2+5)*3
on 15-03-2013 15:50
on 15-03-2013 15:50
Slightly bored this afternoon:
1= (2*3) -5
11=(2*3)+5
15-03-2013 15:55 - edited 15-03-2013 15:57
15-03-2013 15:55 - edited 15-03-2013 15:57
14=(3^2) + 5
3=(2^3) -5
on 15-03-2013 16:22
on 15-03-2013 16:22
6=5+3-2
5=5(3-2)
on 15-03-2013 17:20
on 15-03-2013 20:38
on 15-03-2013 20:38
As an update, so far we have:
0 = 5 - 3 - 2 (Opium)
1 = (2*3) -5 (sheepdog)
2 =
3 = (2^3) -5 (sheepdog)
4 = (3+5) / 2 (version7point0)
5 = 5(3-2) (sheepdog)
6 = 5+3-2 (sheepdog)
7 = (5*2) -3 (sheepdog)
8 =
9 = (5-2)*3 (version7point0)
10 = 5 + 3 + 2 (Opium)
11 = (2*3)+5 (sheepdog)
12 =
13 = (5*3)-2 (version7point0)
14 =(3^2) + 5 (sheepdog)
15 =
16 = (5*3)-2 (sheepdog)
17 = (5*3)+2 (version7point0)
18 =
19 =
20=
21= (2+5)*3 (sheepdog)