on 15-03-2013 13:56
on 15-03-2013 13:56
Here's an interesting game:
Can we make all the numbers from 0 to 21 just by using 2, 3 and 5?
It is possible to do.
So for example;
0 = 5 - 3 - 2
10 = 5 + 3 + 2
on 15-03-2013 21:58
on 15-03-2013 21:58
on 15-03-2013 22:04
on 15-03-2013 22:04
I've just to find the solution for 12 but I won't post the rest til tomorrow...
15-03-2013 22:06 - edited 15-03-2013 22:12
15-03-2013 22:06 - edited 15-03-2013 22:12
20 = 3cubed (-5) (-2)
19 = 2squared (*5) (-3)
Does this constitute using the numbers once?
on 15-03-2013 22:07
on 15-03-2013 22:07
on 15-03-2013 22:08
on 15-03-2013 22:08
on 17-03-2013 17:48
on 17-03-2013 17:48
2 = 2(3! - 5)
8= (3!/2!) + 5
12= 3! + (5-2)!
15= 5!/(3! * 2!)
18= (5!/3!) -2
19 = 5^2 -3!
Though I had a slight variant on 20 than opium did: (3! - 2) * 5.
#12 was a bit of a puzzler but the found the solution during the half time of Wales v England.