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    <title>topic Re: Phone records in Tech Support</title>
    <link>https://community.o2.co.uk/t5/Tech-Support/Phone-records/m-p/1567950#M23950</link>
    <description>&lt;P&gt;&lt;a href="https://community.o2.co.uk/t5/user/viewprofilepage/user-id/4935267"&gt;@Ross100000000&lt;/a&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Records are only available to you for the past 2 years.&lt;/P&gt;&lt;P&gt;O2 keep records for 6 years, so anything beyond the 2 that you can obtain would need to be the subject of a court order or police request.&lt;/P&gt;</description>
    <pubDate>Tue, 16 Aug 2022 20:41:51 GMT</pubDate>
    <dc:creator>MI5</dc:creator>
    <dc:date>2022-08-16T20:41:51Z</dc:date>
    <item>
      <title>Phone records</title>
      <link>https://community.o2.co.uk/t5/Tech-Support/Phone-records/m-p/1567948#M23948</link>
      <description>&lt;P&gt;I am not an O2 customer anymore but used to be. I need my phone records from 2017. Is it possible to obtain these?&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Tue, 16 Aug 2022 20:35:46 GMT</pubDate>
      <guid>https://community.o2.co.uk/t5/Tech-Support/Phone-records/m-p/1567948#M23948</guid>
      <dc:creator>Ross100000000</dc:creator>
      <dc:date>2022-08-16T20:35:46Z</dc:date>
    </item>
    <item>
      <title>Re: Phone records</title>
      <link>https://community.o2.co.uk/t5/Tech-Support/Phone-records/m-p/1567950#M23950</link>
      <description>&lt;P&gt;&lt;a href="https://community.o2.co.uk/t5/user/viewprofilepage/user-id/4935267"&gt;@Ross100000000&lt;/a&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Records are only available to you for the past 2 years.&lt;/P&gt;&lt;P&gt;O2 keep records for 6 years, so anything beyond the 2 that you can obtain would need to be the subject of a court order or police request.&lt;/P&gt;</description>
      <pubDate>Tue, 16 Aug 2022 20:41:51 GMT</pubDate>
      <guid>https://community.o2.co.uk/t5/Tech-Support/Phone-records/m-p/1567950#M23950</guid>
      <dc:creator>MI5</dc:creator>
      <dc:date>2022-08-16T20:41:51Z</dc:date>
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